Q^2+3Q-4=0

Solution for Q^2+3Q-4=0 equation:

Simplifying
Q2 + 3Q + -4 = 0

Reorder the terms:
-4 + 3Q + Q2 = 0

Solving
-4 + 3Q + Q2 = 0

Solving for variable 'Q'.

Factor a trinomial.
(-4 + -1Q)(1 + -1Q) = 0

Subproblem 1
Set the factor '(-4 + -1Q)' equal to zero and attempt to solve:

Simplifying
-4 + -1Q = 0

Solving
-4 + -1Q = 0

Move all terms containing Q to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1Q = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1Q = 0 + 4
-1Q = 0 + 4

Combine like terms: 0 + 4 = 4
-1Q = 4

Divide each side by '-1'.
Q = -4

Simplifying
Q = -4
Subproblem 2
Set the factor '(1 + -1Q)' equal to zero and attempt to solve:

Simplifying
1 + -1Q = 0

Solving
1 + -1Q = 0

Move all terms containing Q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1Q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1Q = 0 + -1
-1Q = 0 + -1

Combine like terms: 0 + -1 = -1
-1Q = -1

Divide each side by '-1'.
Q = 1

Simplifying
Q = 1
Solution
Q = {-4, 1}